2+ds+s(2+(s^2)t)dt=0

Solution for 2+ds+s(2+(s^2)t)dt=0 equation:

Simplifying
2 + ds + s(2 + (s2) * t) * dt = 0

Multiply s2 * t
2 + ds + s(2 + s2t) * dt = 0

Reorder the terms for easier multiplication:
2 + ds + s * dt(2 + s2t) = 0

Multiply s * dt
2 + ds + dst(2 + s2t) = 0
2 + ds + (2 * dst + s2t * dst) = 0
2 + ds + (2dst + ds3t2) = 0

Solving
2 + ds + 2dst + ds3t2 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + ds + 2dst + -2 + ds3t2 = 0 + -2

Reorder the terms:
2 + -2 + ds + 2dst + ds3t2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + ds + 2dst + ds3t2 = 0 + -2
ds + 2dst + ds3t2 = 0 + -2

Combine like terms: 0 + -2 = -2
ds + 2dst + ds3t2 = -2

Reorder the terms:
2 + ds + 2dst + ds3t2 = -2 + 2

Combine like terms: -2 + 2 = 0
2 + ds + 2dst + ds3t2 = 0

The solution to this equation could not be determined.